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How do you solve ln3+ln(2x^2+4)=ln12? | Socratic
x=0 Since lna+lnb=ln(ab), then ln3+ln(2x^2+4)=ln12 is equivalent to: ln(3(2x^2+4))=ln12. that's equivalent to: 3(2x^2+4)=12 6x^2+12=12 6x^2=0 x=0
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