Robuta

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https://mathoverflow.net/posts/509541/revisions Revisions to Elegant identity using Stirling numbers of both kinds and Bernoulli numbers -... identity usingstirling numbersrevisionselegantkinds https://mathoverflow.net/questions/tagged/stirling-numbers Newest 'stirling-numbers' Questions - MathOverflow stirling numbersquestions mathoverflownewest https://mathoverflow.net/questions/510394/identity-with-stirling-numbers-of-the-first-kind nt.number theory - Identity with Stirling numbers of the first kind - MathOverflow Let ${n \brack k}$ be the unsigned Stirling numbers of the first kind. With the luck of intuition and after a lot of numerical experiments I conjecture that $$... nt number theorystirling numbersidentityfirstkind https://mathoverflow.net/questions/509867/identities-with-stirling-numbers-of-both-kinds nt.number theory - Identities with Stirling numbers of both kinds - MathOverflow With the luck of intuition, I conjecture that $$ {n+m+1 \brack m+1} = (-1)^n \sum\limits_{k=0}^{n} \left[ \left[ \sum\limits_{i=0}^{k} (-1)^{k+i} 2^{k-i}... nt number theorystirling numbersidentitieskindsmathoverflow https://mathoverflow.net/questions/474520/recursion-for-the-sum-with-stirling-numbers-of-both-kinds nt.number theory - Recursion for the sum with Stirling numbers of both kinds - MathOverflow Let $s(n,k)$ be a (signed) Stirling number of the first kind. Let $n \brace k$ be a Stirling number of the second kind. Let $$ f(n,m,i) =... nt number theorystirling numbersrecursionsumkinds