Robuta

https://journal.hep.com.cn/fmc/EN/10.1007/s11464-020-0814-4 Auslander's defect formula and a commutative triangle in an exact category We prove Auslander's defect formula in an exact category, and obtain a commutative triangle involving the Auslander bijections and the generalized... commutative triangleexact categoryauslanderdefectformula